combustion equations 4 chemical equations and stoichiometry

Chapter 4Ĭhemical Equations Balancing Chemical Reactions _NH4NO3(s)  _N2O(g) + _H2O(g) Chapter 4Ĭhemical Equations Balancing Chemical Reactions _NH4NO3(s)  _N2O(g) + _2_H2O(g) Chapter 4Ĭhemical Equations Balancing Chemical Reactions _Mg3N2(s) + _H2O(l)  _Mg(OH)2(s) + _NH3(aq) Chapter 4Ĭhemical Equations Balancing Chemical Reactions _Mg3N2(s) + _H2O(l)  _3_Mg(OH)2(s) + _NH3(aq) Chapter 4Ĭhemical Equations Balancing Chemical Reactions _Mg3N2(s) + _H2O(l)  _3_Mg(OH)2(s) + _2_NH3(aq) Chapter 4Ĭhemical Equations Balancing Chemical Reactions _Mg3N2(s) + _6_H2O(l)  _3_Mg(OH)2(s) + _2_NH3(aq) Chapter 4 Law of Conservation of Mass Matter cannot be created or lost in any chemical reaction. Notice that the number of hydrogen atoms and oxygen atoms on the reactant side and the product side is equal.Coefficients are multipliers, in this equation 2 in front of the H2 indicates that there are 2 molecules of H2 in the equation.

The numbers in front of the compounds (H2 and H2O) are called stoichiometriccoefficients.

The materials you make are called Products.

The materials you start with are called Reactants.

When a chemist encounters a new reaction, it does not usually come with a label that shows the balanced chemical equation.- E N D - Presentation TranscriptĬhemical Equations and Stoichiometry Chapter 4 Chapter 4Ĭhemical Equations 2H2(g) + O2(g)2H2O(g) Chapter 4Ĭhemical Equations 2H2(g) + O2(g)2H2O(g) To proceed, the equation must first be balanced.Ī chemical reaction changes only the distribution of atoms, not the number of atoms. If the numbers of each type of atom are different on the two sides of a chemical equation, then the equation is unbalanced, and it cannot correctly describe what happens during the reaction. In this reaction, and in most chemical reactions, bonds are broken in the reactants (here, Cr–O and N–H bonds), and new bonds are formed to create the products (here, O–H and N≡N bonds). A chemical reaction represents a change in the distribution of atoms, but not in the number of atoms.

What is different on each side of the equation is how the atoms are arranged to make molecules or ions.

Combustion equations 4 chemical equations and stoichiometry